ABCDEF

no.. i didnt get it...can u xplain the reactions plzz

"A" is giving Ring test => Anion - Nitrate...

Now fr the cationic part......
Since "B" is a chloride ppt. cation's one of Pb²⁺ , Ag⁺, Hg₂²⁺ (Only 3 main chlorides are insoluble in HCl i.e. the Group 1 Chlorides)

E (Dunno what they r actually asking for....)

In Ammonia (can even consider it as NH₄OH)...Ag⁺ dissolves forming Tetra ammine silver cation, But Mercurous gives a black ppt of Hg with a white one of NH₂.HgCl (but the overall effect is black!) ....so our cation probably is Hg₂²⁺ ion.....
The salt being Hg₂(NO3)₂.

Unable to view the rest of the img part...

OK.

A gives brown ring test. thus its surely nitrate or a nitrite. but nitrate salts are specifically used for standard reactions.

Now, the processes forming B, C, D , G, H clearly says dat G is Nessler's reagent. so, this clearly states dat the ion is either Hg⁺ or Hg²⁺

Now, Hg²⁺ on reaction with HCl gives HgCl₂ , which is colourless. thus the cation is Hg⁺ giving Hg₂Cl₂ on reaction wid HCl which is a white precipitate.

then, HgCl₂ is formed on reaction with Cl₂ water, which is soluble. then, on reaction wid KI, HgI₂ is formed which is an orange precipitate. and then Nessler's reagent is formed , which is used in the detection of NH₄⁺ and gives iodide of millon's base on reaction wid (NH₄)₂SO₄ in alkaline medium.

the two important reactions involved are :

NH₄⁺ + 2[HgI₄]^2- + 4OH^- → HgO·Hg(NH₂)I + 7I^- + 3H₂O

and

Hg₂Cl₂ + NH₃ → Hg ( black ppt.) + HgNH₂Cl ( white ppt.)