In this question fist find the number of moles of B and H in the compound
moles of B = 5.94/ 10 ≈ 0.6
Hydrogen = 1.8/1 = 1.8 ..
so the ratio is 1:3 ..so the hydride wud be like B2H6 or BH3 ..
but in the question we are asked emperical formula so it shud be BH3
A hydride of boran contains 5.94g of B and 1.8 g of hydrogen then the emperical formula of boron hydride would be____
a)B3H6
b)B2H6
c)BH3
d)B4H10
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3 Answers
govind
·2010-03-22 05:15:38
Arka Halder
·2010-03-22 05:18:47
obviously the empirical formula is BH3 as in accordance with govind's working.we cannot say anything about mol formula unless mol wt or vapour density etc are given.
Avik
·2010-03-24 00:46:48
Is Qn mein kuch bhi karne ki zaroorat nahi hai :D
'Coz Empirical Formula is always in the Lowest terms of resp. atoms.....& only (c) is the one thts correct.