HYBRIDISATION

of ICl2-

and the number of lone pairs

steps !!

11 Answers

106
Asish Mahapatra ·

I has 2 bond pair and 3 lone pair .. so hybridisation is sp3d and shape is linear

1357
Manish Shankar ·

sp3d
shape is linear

1
°ღ•๓яυΠ·

sp3d hybirsied hw can it b linear

i mean ya itz linear woh theek hai bt itz contadictin na

1
questions ·

hey whats the method ?

1
questions ·

oxidation state of I is +1 na?

1
big looser ......... ·

in sp3d I will have 3 unpaired electrons but its oxidation state is +1, so how it is possible.

106
Asish Mahapatra ·

hybridisation = no. of lone pairs + no of bond pairs = m

if m=2 then sp and structure is linear
m=3 then sp2 and structure is triangular planar
m=4 then sp3 and structure is tetrahedral
m=5 then sp3d and structure is trigonal bipyramidal
m=6 then sp3d2 and structure is octahedral

shape can be decided by putting the lone pairs in places such that stability will be more

1
big looser ......... ·

if I has 3 unpaired electrons then its oxidation state should be +3, which is not possible

1
questions ·

yeah !!

how to know the number oif lone pairs ?

any method ?

106
Asish Mahapatra ·

take this example ICl2- .. here I- can be considered to have valence shell of 8 electrons... 2 of these electrons are shared with 2 Cl... so remaining unpaired electrons = 6 so lone pairs = 6/2 = 3

1
big looser ......... ·

can u draw the structure asish

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