IIT JEE past questions Salt analysis

AIEEE 2015 Preparation › Inorganic Chemistry questions › IIT JEE past questions Salt analysis

When a white crystalline compound X is heated with K2Cr2O7 and concentrated H2SO4 a reddish brown gas A is evolved. On passing A into caustic soda solution, a yellow coloured solution of B is obtained.
Neutralizing the solution B with acetic acid and on subsequent addition of lead acetate, a yellow precipitate C is obtained. When X is heated with NaOH solution, a colourless gas is evolved and on passibn this gas into K2HgI4 solution, a reddish brown precipitate D is formed.

Identify A<B<C< D< X

give the equations involved.

#Chemistry #Inorganic Chemistry

UP 0 DOWN 0 1 3
Post on FacebookPost anonymously?

3 Answers

21

tapanmast Vora ·2009-03-27 07:39:43

A = chromyl chloride = CrO2Cl2

B = Na2CrO4

C = PbCrO4

X = NH4Cl

D = Millon's base of Iodide = HgOÂ·Hg(NH2)I

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

kamalendu ghosh ·2009-03-27 09:30:24

tapan is bang on target

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

parthiban ·2009-03-28 20:17:05

Equations:-
4NH4Cl + K2Cr2O7 + 3H2SO4 â†’ 2(NH4)2SO4 + K2SO4 + 2CrO2Cl2
X A

CrO2Cl2 +NaOH â†’ Na2CrO4 + 2H2O +2NaCl
A B

Na2CrO4 + (CH3COO)2Pb â†’PbCrO4 + 2CH3COONa
B C

3NaOH + NH4Cl + 2K2HgI4 â†’ HgO.Hg(NH2)I + 4KI + 3NaI + HCl
X D

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω