1Q1 a,c,d all reasons told by avik
@avik C it decomposes to CuO . why did u say C is false???
Q1 True statements regarding copper sulfate
a)it reacts with NaOH and glucose to give Cu2O
b)it reacts with KCl to give Cu2O
c)it gives CuO on st. heating in air
d)it reacts with KI to give brown color
*More than one correct*
Q2 which is insoluble in NH3 soln
a)AgCl
b)AgBr
c)AgI
d)Ag2S
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22 Answers
1
1Q.2) Ans. are c) and d) precisely.
AgCl is a colourless salt soluble even in dil.NH3.
AgCl + NH4OH → Ag [(NH3)2] Cl + H2O
Similarly AgBr is soluble in conc. NH3 solution.
But, AgI and Ag2S are insoluble in NH3 solution
This is a test to distinguish AgI from the other two halides.
11Well, it can't be (a) , (b) bcoz Ag Cl and Ag Br when dissolved in ammonia, they form the ammine complex [H3N → Ag → NH3] + , which is linear.
AgBr dissolves in 0.880 ammonia , but AgI is insoluble in 0.880 ammonia.
So ans should be (c), (d)
19ans 2 > c,d (not sure about (a))
some data to be noted :
with an AgNO3 solution ,acidified with HNO3, HI gives a yellow ppt. of AgI , which is insoluble in ammonia solution !
1Q1 a,c,d all reasons told by avik
@ C it decomposes to CuO . why did u say C is false???
13Q1) a)-True ...(Refer Benedict sol.n frm organic whch reduces Cu 2+ to red Cu2O)
b)-False (Gives CuCl2)
c)-True [Edited] (It will decompose to give CuO only)
d)-True (1st forms CuI2 which disproportionates due to unstabilty giving Cu2I2 & I2 gas...This excess I2 dissolves in KI to give a brown sol.n of KI3)
1AgCl is soluble in NH3 solution(NH4OH)
In aqueous solution of ammonia it gives the following reaction:
AgCl + 2NH4OH → Ag(NH3)2Cl + 2H2O
The complex salt diamine silver chloride formed is soluble and hence AgCl is soluble in NH4OH.
1q2-- NH3 = N3-+3H+
AgCl = Ag+ + Cl-
N3- WILL NOT COMBINE WITH Ag+
SO REACTION WILL NOT OCCUR. HENCE AgCl IS INSOLUBLE.
SIMILARLY BREAK OTHER IONS AND SEE IF U GET FAMILIAR COMPOUNDS BETN OPP CHARGED SPECIES.
3q2) a is soluble in ammonia and b is partially soluble and c,and d is not soluble in ammonia