21hey genius!!!
but then wat expression will u use to find max displacement??
the ans is 0.2m
17 Answers
21
62Always take care of not doing the following!
1) F=μR
2) Drawing FBD with small arrows (showing forces)
3) Not canceling out the original forces when taking components
1Who takes the trouble of typing more letters
when not needed....
by the way u r right.
1i think : we should never take the equality sign in friction questions ...
that will lead to a confusion whether anything that we are getting is maximum or minimum..
here its told 'maximum' so ok....
but this is not always the case...
1i have added the last equation Tapan;
solving those gives max dis. A=0.2m.
as already solved by the girl from sky....:)
1of course it is 0.2 .
all might have got the FBD ..
horizontal : Tcosθ = f ------1
vertical : Tsinθ + N = Mg -------2
f ≤ μN => Tcosθ ≤ (Mg - Tsinθ)
=> T ≤ μMg/ (cosθ + μsinθ) --------3
Tcosθ = kx -------- 4
from 3 and 4 ,
x ≤ (...u can get it... :P )
bus [1]
1u told dog moved 0.25m
then max. force the spring can provide is 400*0.25=100N
THEN how could tension b more than 100N
1subhash ,,,,
can u tell what will b the value of tension in the string ??
and d direction of friction?