i"m sorry it is K3{Cr(O2)4} THE ANSWER GIVEN IS +13 BUT HOW IS THAT POSSIBLE ???
WHAT IS THE OXIDATION NUMBER OF CHROMIUM IN [Cr (O2)4]
PLZ SOMEONE REPLY..
THE OXIDATION NO FOR EACH O IN (O2) IS -2??????
-
UP 0 DOWN 0 0 7
7 Answers
Vinay Arya
·2011-02-10 07:01:00
I think you have mistyped somewhere.or the question is wrong.How can it have oxidation state to be +16?
bhaarat
·2011-02-10 07:24:36
Vinay Arya
·2011-02-10 21:35:14
To send Cr to such a high oxidation state too much huge amount of energy is required,which is not possible.
qwerty
·2011-02-13 08:23:06
Cr is in +5 here. All Oxygen are involved in peroxy linkage , i.e each O has ON= -1 ..