1Wrong answer !!!!!
check it again ..there is a silly mistake .
n0/2 atoms of X(g) are converted in to X+ (g) by energy ∆H,KJ .n0/2 atom atoms of X(g) are converted in to X+(g) and n0/2 atoms of X(g) converted in to X-(g) by energy ∆H2. calculate the ionization energy and electron affinity of X .
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5 Answers
106X(g) --> X+(g) ΔH (for 1/2 mole)
so ionisation energy = 2ΔH as ionisation energy is calculated per mole
X(g) --> X+(g) + X-(g) ΔH2
now ΔH2 = ΔH + EA/2 (as only half mole is ionised to X-)
=> EA = 2(ΔH2 - ΔH)
11Let the I.E of X be I and electron affinity of X be E kj/mol .
X(g)→X+ (g)+e
[1/(NA V)×N0/2]=∆H
I =[(2∆H×NAV)/N0] kj/mol
(where NAV is the Avogadroâ€s no)
Similarly
X(g)→X+ (g)+e
X(g)+e→X- (g)
∆H+[E/(NA V)×N0/2]=∆H2
E = ((2(∆H2-∆H))/N0 ) kj/mol
Got the answer !!
see where u did mistake !!
106I thought that N0 is Avogadro's no. we use NA or No as avogadro..
1in every question..if avogadro number is given ..it will be stated to you ..but if not you should not consider.
so be aware !!