1
sakshi pandey pandey
·2009-12-12 02:44:43
for N- anion .........
no of electrons in valence shell= 6
sheilding constant for 2p orbital = .35 x 5 + .85 x2 = 3.45
derefore z (eff) = 7- 3.45 = 3.55
for N + cation
no of electrons in valence shell = 4
sheilding constant = .35 x3 + .85 x2 =2.75
derefor z( eff) = 7 - 2.75 = 4.25
1
mentor_Layak Singh
·2009-12-12 02:51:05
for N + cation
electron in the outermost orbit is screened by 4 electrons in nth orbit and 2 electrons in (n-1)th orbit.
no of electrons in valence shell = 4
sheilding constant = .35 x4 + .85 x2 =3.10
derefor z( eff) = 7 - 3.10 = 3.90