1H2SO4 + HI → I2 + SO2 + H2O
K2Cr2O7 + HCl → KCl + Cr2O3 + Cl2
CaOCl2 + NaI + HCl → NaCl + CaI2 + Cl2 + H2O
8 Answers
1
24tell me how did u write the products ??
this is one thing I am very weak in....can u explain how did u do that ?
1see , 1st one is a standard redox reaction in which H2SO4 ,being a strong oxidising agent oxidises I- to I2 and itself gets reduced to SO2.
2ND ONE : same as the 1st one . here K2Cr2O7 acts as a strong oxidising agent carrying out the redox reaction.
3rd one is a bit complicated. in it,i first did the reaction of HCl and CaOCl2 forming CaCl2 and HOCl. now reaction of the products wid NaI , forming the above products.
243rd
but why didnt CaOCL2 and NaI or NaI and HCl react in first step ???
24hmmm
so if CaOCL2 and NaI react what will be intermediate product ??
or if NaI and HCl react?
1dude,first of all CaOCl2 and NaI will not react at all in the anhydrous state. because fr this reaction 2 take place , H2O needs 2 be der to first dissisiate CaOCl2 into Cl2 and Ca(OH)2 and the products ( especially Cl2 reacts wid NaI ).
and fr the combination of NaI and HCl , de'll form NaCl and HI . now, HI reacts wid CaOCl2 to frm the remaining products i.e. CaI2 + Cl2 + H2O