VOLUMETRIC AnALYSIS

11 Answers

11
Mani Pal Singh ·

bhai dont get confused by the factors
write the reactions u will come to know about it .it represents the no of moles req for the oxidation /reduction of 1 mole of substance
(EDITED TO PREVENT CONFUSION)[1]

21
tapanmast Vora ·

ARE U SURE : dat it is da valence charge charge present on Cr & Mn respectively? Mujhe to laga tha it wud b change in ox. state of Cr & Mn Pre and Post REACDTION wid KI in acidic med.

CAn U tell me y do u say its valence charge nad not the CHANGE IN OX. STATE

21
tapanmast Vora ·

CHK AGAIN : CHARGE ON Mn in KMnO4 = 8-1 = 7

11
Mani Pal Singh ·

bhai read the 1st statement

REACTIONS R TO BE WRITTEN OFF TO GET THE SOLUTION
THE CHANGE IN THE OXIDATION NUMBER IS THE THING WHICH COUNTS...................

1
skygirl ·

yes tapan u are right..

wahi hai jo tumhe laga tha..

it is the change in oxidation state..

not the valence charge

Mn 7+ -----> Mn2+ change of 5 .. so eq wt= mol wt/5

Cr2 12+ -------> Cr26+

change in ox state per formula wt = 6

so eq wt = molwt/6

i think it is ok now... [1]

1
AARTHI ·

yehi toh hain na...n-factor....for kmno4 it is 5 and for for cr it is 6

.: eqwt...= mol wt/ n-factor

hey...im rite na ...im not confusing any1?

21
tapanmast Vora ·

Aarti : hope u know : n-Factor is not CONSTANT for a compound!

It depnds on the product wich helps find CHANGE IN OX. STATE!!!

1
skygirl ·

tapan did u get it ?

21
tapanmast Vora ·

YAH!!! absolutely!! Thnx [1]

1
skygirl ·

k..

1
AARTHI ·

yah ...i knoww...dats y i told dat for dis rxn...da n fctor for mn and cr dey are 5 and 6 respectively

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