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this ques came in bitsat today in one of my frends paper find out the next term 4,31,60,121.... i dun hav the options yeah jus two of them 243 or 242 dunno wats the ans,..... ...
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A frnd of mine gave me this sum to solve but i am not being able to do so...(cant match the ans)... the q is: x2+y2+z2=27 then x3+y3+z3 has: a) min value 81 b)max value 81 c)min value 27 d) max value 27 ans: b) ...
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(A):22225555+55552222 is divisible by 7. (R):xn-an is divisible by x-a,n is even or odd and xn+an is divisible by x+a if n is odd. answer is A.............jus tell me how is reason explainin the assertion part?? ...
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here is a typical number theory problem. i hav tried this but was unable to solve this sum. i figured out the answer but could not proceed in any logical method. could you please tell me some logical step-by-step method for r ...
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1) Show that if a diagonal matrix is commutative with every matrix of the same order, then it is necessarily a scalar matrix. 2)Find the possible square roots of the two rowed unit matrix I. 3) If M is a 3x3 matrix where |M|= ...
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There are n stones in a line , the distance betwen the consecutive stones being 1m ,3m,5m etc. There is a basket fixed at the first stone.A man starting from the baskets collects all the stones in the basket one by one . Find ...
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The funtion f(x) = [x]2 - [x2] (where [] is GIF) is discontinuous at a.All integers b.All integers exvept 0 c.All integers except 1 d.All integers except 0 and 1 ...
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1. If a = i + j + k , b = 4 i + 3 j + 4 k and c = i + a j + b k are linearly dependent vectors and |c| = 3 , then (1) a = 1, b = - 1 (2) a = 1, b = ± 1 (3) a = - 1, b = ± 1 (4) a = ± 1, b = 1 ...
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1. The solution of the inequality 2x-5/|x-3|>-1 is a)(2,∞) b)(3,∞) c) (2,3) 4) (8/3,∞) ...
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solve question of bitsat i m not able to provide option *Image* ...
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A square of n units by n units is divided into n2 squares of 1 sq. unit each. find the number of ways in which 4 points ( out of (n+1)2 points) be selected so that they form the vertices of a square. i was able to count the n ...
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Here are the Questions i could remember ..... Q.1. What should be the values of x and y such that x2 + y2 is minimum and (x + 5)2 + (y – 12)2 = 142 ?? I got the answer as (x, y) = ( 5/13, -12/13 ) and min value as 1 Q.2. so ...
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81sin2x + 81cos2x =30, then the least value of x,(x>0) is what? plz help! ...
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we all know that 0<={x}<1 .. is also, 0<={-x}<1????? i think yes... but saw recently in a practice paper whch says the reverse,,...!!! MAY DAY!! ...
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please post your methods so that we can have a good discussion its not a difficult one Prove that \frac{\sin ^{3}a}{sinb}+\frac{cos^{3}a}{cosb}\geq sec(a-b) for all 0< a,b <Ï€/2 ...
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Lim ( n → infinity) { (1/2) tan x/2  + (1/22) tan x/22 + (1/23) tan x/23 .............+(1/2n)tan x/2n) } ...
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Prove that 2mn> mn as well as nm Find the shortest proof. HINT : this is in syllabus oops sry, condition: n,m>0 and ε N ...
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THE VALUE OF LIM ( N→ INFINTIY ) (N ! / NN)(2N4+1)/(5N5+1) IS A. 1 B. 0 C. e-2/5 d. e2/5 ...
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let f(x) and g(x) are two differential functions and the limit of the function lim ( n → infinity ) { (x2nf(x) + x 100g(x))/(x2n +1)} exists at x= 1 , then the equation f(x)=g(x) has a. at least one real root in (0,2) b. no ...
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Q) Two rectangles are given.The Area of the 1st rectangle is double the area of the 2nd rectangle.The Perimeter of 2nd rectangle is double the perimeter of the 1st rectangle.Then Find the Sides of the 2 rectangles? Plz give t ...
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limn→∞(nαsin2n!/n+1), where 0<α<1 ...
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i am not sure wether u can say as to it is in jee syllabus or not but kindly post your thoughts and methods so that we can have a good discussion find all polynomials f satisfying f(x)f(-x)=f(x^{2}) ...
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A car is parked among N cars standing in a row, but not at either end. On his return, the owner finds that exactly 'r' of the N places are still occupied. The probability that both the places neighbouring his car are empty is ...
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Prove that for any complex number z, |z + 1| ≥1/√2 or |z2 + 1| ≥ 1. ...
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x+10+6 3 = 1+ 3 -x find x ...
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let 'x' be positive non-square integers such that x1=2, x2=3, x3 = 5, x4=6 .. and so on... and we define <m> such that if the decimal part is <=0.5 we have <m> =m and if decimal part >0.5 , then <m>=m+ ...
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f(x) = lim (n→ infinity) n( x1/n -1) , x>0 then f(xy) is a. f(x)f(y) b. f(x)+f(y) c. y f(x) + x f(y) d. N.O.T ...
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If the valences 1,1/2,1/3,1/4....occur at frequency 1,2,3,4,5.......,n in a distribution then the mean is : a. 1 b. n c. 1/n 4.NONE ...
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Prove that √(7/2) ≤ |1 + z| + |1 − z + z2| ≤ 3√(7/6) for all complex numbers with |z| = 1. ...
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The line y=3x bisects the angle between pairs of lines ax2 + 2axy + y2 = 0 if a = 1. 3 2. 11 3. 3/11 4. 11/3 ...