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A computer solved several problems in succession. The time it took the computer to solve each successive problem was the same number of times smaller than the time it took for the preceding problem. How many problems were sug ...
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the integer just grater than (√3+1)^6 ...
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g(x) = x5 + x4 + x3 + x2 +x +1 wats the remainder wen the polynomial g(x12) is divided by the polynomial g(x) ? a) 6 b) 5 - x c) 4- x - x2 d) 3 - x + x2 - x3 ...
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LIMITS.....plz solve *Image* *Image* ...
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Given that n4<10n for a fixed positive integer n≥2, then prove that (n+1)4<10n+1 ...
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If a1's are all +ve real numbers then prove that: (1+a1+a12)(1+a2+a22).........((1+an+an2)≥3na1a2..........an ...
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Find the term independent of x in the expansion of (x2/3+4x1/3+4)5 . [1/(x1/3-1) + 1/(x2/3+x1/3+1)]-9 ...
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Q1)∫0pi/4 sin x+cos x/9+16sin 2x Q2)∫0 pi/2 sin2x tan-1(sinx)dx ...
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If α and β are roots of z +1/z =2(cosθ+isinθ) ,0<θ<π then show that mod(α-i)=mod(β-1) ...
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xn+1= 0.5(1+xn) , n≥0 Then, cos( 1-xo2 /x1x2x3....∞)=? ...
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Q I = 0∫π log(1+cos x)dx ...
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Integrate: ∫dx/sin4x+cos4x ...
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if a1,a2,a3,....,an are +ve real nos whose product is a fixed real no. 'c', then the minimum value of a1+a2+a3+......+2an-1 + 2an is -- a) n(4c)1/n b) (n+1) c 1/n c) 2nc1/n d) (n+1)(2c)1/n ...
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S is a parabola y2=4ax A is the vertex AP and AQ are 2 chords which make angle π/4 with each other Also PQ is a focal chord Then what is the area of triangle APQ ...
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*Image* ...
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If the lengths of medians are 2 unit,3 unit,4 unit,then the area of the triangle is A)Area >4 3 B)Area <4 3 C)Area≥4 3 D)Area≤4 3 ...
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hey plz check this one i m getting the ans ln(x/x+1)+1/x-1/2x2+c *Image* ...
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fund the condition such that (2x-1)/(2x3+3x2+x)>0 ...
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prove that all pts lying inside triangle formed by pts. (1,3),(5,0),(-1,2) satisfy 3x+2y≥0 and 2x+y-13≥0 ...
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if a,b >0 satisfy a3+b3=a-b , then.. a) a2+b2=1 b) a2+b2>1 c) a2+b2+ab < 1 d) not. ...
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What is the range of 1) sin(cos(tan x)))? 2) cos(sin(tan x)))? 3) tan(cos(sin x)))? ...
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Lt x→0 (1+3x+2x2)^(1/x) ...
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digit in units place of the number 1!+2!+3!+...........+99! is? ...
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Find last digit of (2004)5 is? ...
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which is greater? 99^n + 100^n or 101^n??? If you get ambiguous answers then specify the intervals for which 99^n+100^n is greater than 101^n or less than it. ...
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PROVE THIS ENQUALITY..... 2n ≥ 1 + n 2(n-1)/2 ...
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The inervals for which x11-x8+x5-x2+x>0 ...
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if I = 0∫1 dx/ [(5+2x-2x2)(1+ e2-4x)] and, I1 = 0∫1 dx/ (5+2x-2x2) , then... a) I = I1 b) I = 2 I1 c) 3I = 5 I1 d) not. ...
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find the value of : : : 18.21.25 + 73 + 183 =---------------------------------------------------------------------------------------------- 64+ 3.6.32 +9.15.16 + 8.20.27 + 4.15.81 + 2.6.243 +36 ...
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y=√x+√y+√x+√y+............to ∞ then dy/dx= ...