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1) Prove that ∫x3 2ax-x2 dx=7πa5/8. 2) Integrate: [ x4/(1-x4)] *cos-1(2x/(1+x2). Upper limit=1/ 3 ;Lower limit=-1/ 3 . 3) Integrate::: 2-x2/[(1+x) 1-x2 ].Upper limit=1;Lower limit=0. 4) Integrate:::: log(1+tanx) from 0 to ...
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Let f(x) be a non constant twice differentiable function defined on (-∞,∞) such that f(x)=f(1-x) and f'(1/4)=0.Then a) f''(x) vanishes at least twice on [0,1] b) f'(1/2)=0 c) ∫(frm -1/2 to 1/2)f(x+1/2)sinxdx=0 d) ∫(fr ...
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*Image* ...
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evaluate *Image* answer given is π2. ...
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The average cost (Rs. y) of a monthly output of x tons of a irm producing a valuable metal is Rs.((x2/10)-3x+62.5).sHOW THAT THE AVERAGE VARIABLE COST CURVE IS A PARABOLA.fIND THE OUTPUT And The cost at the vertex of the para ...
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2.the girder of a railway bridge is a parabola with its vertex at the highest point 15m above the ends.if the span is 120 m find the height of the bridge at 24m from the middle point. ...
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*Image* ...
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Integrate:: 4x3[d2/dx2(1-x2)5]dx from 0 to 1.Here d2/dx2 means the double derivative of the function w.r.t.x. This sum is meant for students only ,not for experts. ...
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{} is fractional func [] is GIF | |is mod *Image* 5. ∫(0 to x)ex-[x]d{x} 6. ∫(0 to 4){ x }dx 7.∫(-5 to 5)min({x+1},{x-1})dx ...
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consider the integrals *Image* let I be the greatest among them. prove that I=I4 ...
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Integrate: 1) (1+x-2/3)/(1+x) 2) cos2x /sinx 3)(x2 + n(n-1))/(xsinx+ncosx)2 ...
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1) Let f:R to R be continuous function which satisfies f(x)=∫(0 to x)f(t)dt, then the value of f(ln5) is: a)0; b)2; c)4; d) 6. 2) Let I=∫(0 to 1) (sinx)/ x and J=∫(0 to 1) (cosx)/ x .Then which is true? a)I<2/3 and J ...
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*Image* ...
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*Image* ...
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If x>0 then integrate (2x-[2x])2 from 0 to 100[x] where [.] means G.I.F. ...
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25)For equation mx + 3 = 7 - x, if x = 4 is the solution, then m = 1 -1 0 4 Your Answer c Correct Answer b Your Score -1 WHY? ...
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*Image* Post your solutions ...
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Find the square root of ((0.75)^3/1-(0.75)) + (0.75 + (0.75)^2 + 1). My problem is that I am getting an answer 2.5 which is NOT one of the options provided. ...
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∫ dx/cosx + cosec x ∫ 3cot3x - cotx/tanx - 3tan3x ∫tan{x -k}tan{x+k}tan2x ...
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Find all values of x which satisfies this equation, sin5x+cos3x=1 ...
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try this integration: \frac{x^{2}-2}{x^{3}\sqrt{x^{2}-1}} ...
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\sqrt{x+\sqrt{x+\sqrt{x+}..}}=y \sqrt{y+\sqrt{y+\sqrt{y+}..}}=5 find √(x+y) ...
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Let f:R->R be continuous function which satisfies f(x)=0∫x f(t)dt, then the value of f(ln5) is: (a) 0 (b) 2 (c) 4 (d) 6 ...
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Let f(x ) = x3 + 3x + 2 and g (x ) is the inverse of it. Find the area bounded by g (x ), the x-axis and the ordinate at x = – 2 and x = 6. ...
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*Image* ...
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∫√(sin x-sin3x/1-sin 3x)dx ...
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2^sinx+2^cosx>1 ...
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√(tanx+2)dx ...
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*Image* ...
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*Image* ...