1
u mean black line(made by me) is distance travelled by car (42km/h one)
A car travelling at 60km/h overtakes another car travelling at 42km/h.assuming each car to be 5m long find the total road distance used for overtake
nishant sir,plz give the solution.
-
UP 0 DOWN 0 0 15
15 Answers
62This is from hcverma na.. i guess someone else also had a trouble
The answer comes short by 5 because the length o fthe car has to be added :)
1let it overtake at time t
then 35t/3+10=50t/3
t=2.
this is first part of ques. which i got correct.
next total road distance used =35t/3+5+5
=33.33=33
why to add 5??????????????
62sorry i deleted my post.. i made a mistake took 5 not 10 :P
Let me post the image and my understanding of the question..
62
The green line gives the total distance travelled by the black car..
Orange shows the length of the road used..
11with wat minimum speed shud a motorbike be moving on the road to safely cross a 11.7ft wide ditch with approach roads at an angle of 15 degree with the horizontal.assume length of bike is 5 ft and it leaves the road as soon as front part runs out of approach of road.
11Range = u2Sin2θ/g
16.7 = u2/2*32
u2 = 32* 33.4
u ≈ 32 ft/sec
11The range will 11.7 + 5 ft
+5 sine the bike will be stable only if it cross the pit and lands with the back will also on the road. Since the length is 5 ft you have to add it
1read ques. properly virang
range will be 11.7+5cos 15+5cos 15
62John I dont see too much wrong in the discussion between you and virang!
1OK JUS TELL range will be 11.7+5cos 15+5cos 15 OR NOT?WHY?????????