f1 = 2v/2l
f2= nv/4l
so, f2=n f1/4
n=4f2/f1
open pipe is in resonance in 2nd harmonic with frequncy f1.Now one end is closed and frequncy is increasd to f2 such taht resoance is in nth harmonic.Find n and relation b/w f2 and f1
thats the soln every book has...but for closed pipe..frequncy is (2n+1)v/4l
and not nv/4l
ya bhaiya but when said nth harmonic then it is nv/4l isn't it.
for nth overtone
it will be (2n+1)v/4l
f1=vl ( 2nd harmonic of open pipe )
f2=n(v4l (nth harmonic of closed pipe )
here f2 > f1 and that is possible when n=5 i.e; f2=54(vl ) = 5/4 f1
hence we get n =5 and f2 = 54 f1