if no friction is there on the incline then force exerted is zero.
if friction is there then force exerted will be resultant of the normal force and the frictional force exerted.
A block moves down an incline with a constant velocity. What is the force exerted by the incline on the block ?
if no friction is there on the incline then force exerted is zero.
if friction is there then force exerted will be resultant of the normal force and the frictional force exerted.
how is that?
if there is no friction then the force exerted by the incline ought to be a component of (mg)...how come ZERO????
also,if you say it is an incline and if friction is present then the force exerted by the incline on block is mg(√cos2θ + sin2θ) = 1
.....suitably choose θ///////point out any flaws,if any !
And friction will have to be there as the net force is zero....aree block ka horizontal component hai ki nehi re ? So debotosh organic chemistry chatterjee is correct.