Angular momentum

A dog of mass m is standing on the edge of a stationary horizontal turntable of totational inertia I and radius R. The dog walks once around the circumference of the turntable.

What fraction of a full circle does the dog's motion make with respect to the ground? Express your answer in terms of m, I and R. Ignore friction at the axle of the turntable.

We can conserve the angular momentum to get-
mvR = I(omega) where v is the velocity of dog w.r.t ground and omega is the angular velocity of the turntable w.r.t ground

No idea after this.

2 Answers

62
Lokesh Verma ·

about the hinge.. or the center of the table..

the force by the dog on the table = force by table on dog (opposite in direction)

so the torque is equal... but opposite in direction

so I1α1 = -I2α2

integrating we get I1ω1=-I2ω2 (constant of integration will be zero because initally they were at rest..

Integrating again, we get I1θ1=-I2θ2

we know that θ1+θ2= 2pi

now solve [1]

1
swordfish ·

ahaan...thanks alot!

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