ATTRACTION

FIND THE FORCE OF ATTRACTION ON A PARTICLE OF MASS m PLACED AT CENTREA OF A SEMICIRCULAR WIRE OF LENGTH L AND MASS M

12 Answers

13
deepanshu001 agarwal ·

GMmpie/LR

is that the ans

13
deepanshu001 agarwal ·

arrey yaar

whr R= L/pie

is it fyn nao...

13
deepanshu001 agarwal ·

kk....can i hav the options
plz...

1
JOHNCENA IS BACK ·

no.....no options available

13
deepanshu001 agarwal ·

giv the ans then .....hide it

i jus cnt get whr did i go wrong

13
deepanshu001 agarwal ·

\int_{}^{}{}M/L*Rd(theita)/R^2

limit 0 to pie

13
deepanshu001 agarwal ·

ab to temme the ans atleast so tht i can figure out whr did i go wrong

13
deepanshu001 agarwal ·

whr do u think i went wrong

13
deepanshu001 agarwal ·

shit i got it man...w8 i ll tel u the ans...

13
deepanshu001 agarwal ·

is the ans

2GMmpie/L^2

13
deepanshu001 agarwal ·

oh my god ...finally'''

i got it

dimaag mein jang lag gaya hai

its rili simple....

actually here we hav to do vector integration
i mean resolve the force into components and then integrate

in the above expression mak the limits -pie/2 to pie/2

and also bring a cos thieta term in the integral

the sin component gets cancelled

13
deepanshu001 agarwal ·

wud ny1 plz lyk to pink this 1

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