BITSAT

AIEEE 2015 Coaching › Mechanics questions › BITSAT

An ice-skater, weighing 60 kg moving at 10 m/s glides to a stop. If 80% of the heat generated by friction is
absorbed by the ice, the amount of ice melted will be nearly
(1) 30 g (2) 14 g (3) 7.1 g (4) 4.1 g

#Physics #Mechanics

UP 0 DOWN 0 0 4
Post on FacebookPost anonymously?

4 Answers

deepanshu001 agarwal ·2009-05-16 03:37:41

is the ans the third option...

UP 0 DOWN 0
Post on FacebookPost anonymously?

sparkle2009 ·2009-05-17 02:27:36

yes,how to do that?

UP 0 DOWN 0
Post on FacebookPost anonymously?

106

Asish Mahapatra ·2009-05-17 03:01:03

amount of heat liberated due to friction = change in KE of body = 60*100/2 = 3000 J
heat absorbed to melt the ice = 0.8*3000 = 2400J = 2400/4.2 cal

amt of ice melted = Q/L = (2400/4.2)/80 gm
= 7.1 gm

UP 0 DOWN 0
Post on FacebookPost anonymously?

Gone.. ·2009-05-17 06:46:42

option 3 i think

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

BITSAT

4 Answers

Your Answer

Add Image

Similar Questions