Two persons A nad B, each carrying a source of sound of frequency 600 Hz are standing a few meters apart in a quiet field. The beat frequency heard when A moves towards B with a velocity of 3 ms-1 ( velocity if sound is 340 ms-1) is
A) 1800337 Hz by A B) 1800340 Hz by A C) 1800340 Hz by B D) 600337 Hz by B
-
UP 0 DOWN 0 1 1
1 Answers
Anirudh Kumar
·2010-02-28 22:06:59
f=f1-f2
= 600( 340/340-3)-600 applying Doppler for the source.
= 600(3/337)
= 1800/337 Hz
A)