1see basically d rise fall and all crap is due to pressure difference...in the case of free falling the net force becomes zero...hence no rise
actually the acceleration due to gravity becomes void
A capillary is dipped in water vessel kept on a freely falling lift, then
a)water will not rise in the tube
b)water will rise to the maximum possible height of the tube
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9 Answers
11Are you sure the capillary action is due to pressure difference?
In the derivation part (pg no 290 HCV vol 1) it is mentioned that the pressures at the top and bottom of the capillary tube cancel each other and we equate S 2 π r cosθ = mg
1are dude whatever the reason the funda is that no force will act....and i dont believe in magic...lol
if u consider the equation uve mentioned ...just place g=0...which is the case for free fall
1what is actually bothering me is the solution given
it says h=(2Scosθ)(rÏg)
as this is the case of free fall g→0 hence h→∞ hence the option (b)
but it might also mean that cosθ=0, i.e, the water doesn't rise at all, hence the option (a)
which logic is correct?
1i dont understand y do people dwell over solutions ?
something which is understood need not be solved
1I found a similar thread which confirms the option (b)
thank you for attempting the question
http://targetiit.com/iit-jee-forum/posts/solve-this-easy-one-11448.html