Circular Motion

5 Answers

1133
Sourish Ghosh ·

a) 12mv02 = 12kx2, x = Rθ
b) 12mv02 = 12kx2 + 12mv2, x = RÏ€4
atotal = √[(v2R)2 + (kxm)2]

865
Soumyadeep Basu ·

θmax=π2.
Magnitude of acceleration at θ=π4 is 25√(916+1π2).

213
Nandikesh Singh ·

I am also getting the same answer.

486
Niraj kumar Jha ·

Yeah,θmax=π2
Net Acc.=25√(916 +1π2)

1161
Akash Anand ·

Some one keep posting solution in short.

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