a) 12mv02 = 12kx2, x = Rθ
b) 12mv02 = 12kx2 + 12mv2, x = RÏ€4
atotal = √[(v2R)2 + (kxm)2]
5 Answers
Sourish Ghosh
·2014-03-01 05:47:41
Soumyadeep Basu
·2014-03-01 01:19:48
θmax=π2.
Magnitude of acceleration at θ=π4 is 25√(916+1π2).
Nandikesh Singh
·2014-03-01 01:44:27
I am also getting the same answer.
- Akash Anand Excellent work ..Upvote·0· Reply ·2014-03-01 04:14:22