CIRCULAR PROBLEMSSS

a track consists of two circular parts ABC and CDE of equal radii 100m.a cycle weighing 100 kg together with rider travels at a constant speed of 18km/h on track.what shud be the minimum friction coefficient b/w road and tyre.

9 Answers

1
JOHNCENA IS BACK ·

reply !!!!!!!

39
Dr.House ·

http://targetiit.com/iit_jee_forum/posts/ek_acha_ques_4449.html

1
JOHNCENA IS BACK ·

@b555
this is an irrelevant post u have posted here!

9
Celestine preetham ·

tangential acc is 0 always

let vector from centre inclined at θ with vertical

μN ≥ mgsinθ

N= |mgcosθ - mv2/r|

μ ≥| sinθ/(cosθ - 1/40)|

this is max wen θ = 45 (at A)

μ≥40/40 -√2

1
kamalendu ghosh ·

HC VERMA..hehe

1
JOHNCENA IS BACK ·

N= |mgcosθ - mv2/r|.............

Y U TOOK THIS Y NOT N= |mgcosθ + mv2/r|

1
JOHNCENA IS BACK ·

n one more thing y u took

μN ≥ mgsinθ...why inequality for zero tangential acceleartion = shud be there

1
JOHNCENA IS BACK ·

CELESTINE REPLY!!!!!!!1

9
Celestine preetham ·

#7 they r opposite wen θ acute
and same direction wen θ obtuse
both these facts are contained in taking

N= |mgcosθ - mv2/r|.............

#8 bcos friction can adjust itself to a lesser value if required

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