coefficient of restitution.................

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A ball of mass m moving with speed v makes head on collision with identical ball at rest.The KE of the balls after collision is 3/4 of original KE.Calculate e.

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Manish Shankar ·2008-12-24 10:51:08

v=v1+v2

(v1²+v2²)/v²=3/4

e=(v2-v1)/v

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Lokesh Verma ·2009-01-01 01:51:58

Momentum conservation: mv=mv1+mv2
Thus, v=v1+v2

(v1²+v2²)/v²=3/4

(v1²+v2²)/(v1+v2)²=3/4

(v1²+v2²)/(v1²+2v2²+v1v2)=3/4

1-(v1²+v2²)/(v1²+2v2²+v1v2)=1-3/4 = 1/4

(2v1v2)/(v1²+2v2²+v1v2)=1/4

Thus, (v1-v2)²/v²=1/2

e=(v2-v1)/v = 1/√2

Chekck for calculation mistakes :)

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coefficient of restitution.................

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