COLLISION

didn't get your question

See 2mV is the change in momentum but monemtum remain constant and conserved as it is MV before and after only the change is 2mv
Therefore both kinectic and momentum is conserved

u din get my ques.

kinetic energy will remain conserved as wall has initial as well as final velocity=0.

so Ki=Kf=1mV²/2

right....

now the momentum shud also be conserved.

so,P_{ball i} =P_{ball f}+P_{wall f}

right...

this gives
mv=-mv+0(since final velocity of wall is 0)

now how will u account for this.......clearly momentum is not conserved..but in priniple it shud be conserved

@anirudh momentum is a VECTOR.
@john cena :

See that the ball applies a force on wall. but earth keeps the wall in place by applying a opposite force. so external impulsive force is present. So we cannot conserve momentum.

Ideally if m2 is too large than m1 then the force on m2 is too small to give it a perceptible acceleration. Now in this case the collision though assumued perfectly elastic is never realised in practice.
In fact the wall should have moved if earth were not there.

Since wall applies an impulse on ball,so we cant conserve momentum along common normal for the ball.....but we can surely do that for wall+ball system becoz then impulses become internal...

@cena, ur post #5 is not correct either way...
taking ball +wall as system, eqn of momentum along common normal will be Pball _i +Pwall _i =Pball _f+Pwall _f