3sry didnt see m' .. took all thre masses as m ... but logic is same..
Two equal spheres of mass m' are suspended by vertical strings so that they are in contact with their centres at same level. a third equal sphere of mass m falls vertically and strikes elastically the other 2 simultaneously so that their centres at the instant of impact form an equilateral triangle in a vertical plane. if u is the velocity of m just before impact, find the velocities just after impact and the impulse of tension of the strings.
-
UP 0 DOWN 0 0 2
2 Answers
3
final velocity of ball falling vertically down ...
5u/7 upward ...
impulse on string = 6mu/7 ...
velocity of the balls attached to string .. 2root(3)u/7 ......
and check answers calc. errors possible .....
3