COM+projectile

A particle of mass 2m is projected at an angle of 45 wrt horizontal wid a velocity of 20√2 m /s .After 1 s explosion takes place and the particle is pbroken into two equal pieces .As a result of this one part comes to rest.Find the maximum height achieved by the other part.

4 Answers

1
Arshad ~Died~ ·

apply conservation of momentum principle,,,,....find velocity.....and hence the distance

6
nix_13 12 ·

will v be =40√2m/s???

1
aeroish ·

yes it will be so v = 40√2m/s

6
nix_13 12 ·

arre yar phans gaya hu yar.........koi solve karke batao

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