u have not given values....
but the concept should b that it will accelerate from a to b(both rotationally and linearly)
and after that it will accelerate only linearly.calculate the values using this info.
was this useful.
portion AB of wedge is rough and BC is smooth.A solid cylinder rolls without slipping from A to B.If AB=BC,then the ratio of translational KE to rotational KE when cylinder reaches point C is??
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7 Answers
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at B mgh/2=1/2mv2+(1/2)mr2/2ω2=3/4mr2ω2
v =ωr
h is total ht of wedge...
now from B to C only trans KE will increase by mgh/2 and rot KE will be same so...
at C
Tran KE=1/2m(ωr)2+mgh/2
put mgh/2 from above...
trans KE=5/4mr2ω2
now rot KE is same as that was at B i.e. (1/2)mr2/2ω2
trans KE at C = 5/4mr2ω2
rot KE at C mr2ω2/4
hence 5:1..
[1]
is it alr8...
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