let the mass per unit length of the chain be λ
λgl -T =d/dt {( l- x/2) * λ*v}
=>T=1/2 (λv2 + 3gx)
A uniform chain of length l and mass m is hanging vertically from its ends A and B which are close together . At a given instant the end B is released. What is the tension at A when B has fallen a distance x [x<l] ?
Ans : mg2 (1+3xl )
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2 Answers
Debotosh..
·2009-11-30 00:17:48