1) 888 Hz
A man stands on the top of a high building with a source of sound with frequency 1000 Hz.He accidently drops the device.Find the frequency of the sound heard by the man 4 seconds after he drops the device?(Speed of sound=320 m/s,g=10 m/s2)?
1)888 Hz
2)860 Hz
3)894.75 Hz
4)930 Hz
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4 Answers
Soumyabrata Mondal
·2013-03-03 22:13:33
na=(vv-vs)no
vs→velocity of the source = 40m/s
v →Speed of sound=320 m/s
no→1000 Hz
- Gaurav Gardi vs=-40m/sUpvote·0· Reply ·2013-03-03 22:29:49
- Soumyabrata Mondal sorry, typng mistake :(
Ketan Chandak
·2013-03-04 00:04:38
dude...did the same thing...got the same answer....but the answer given is not that...
- Gaurav Gardi is it (3)
- Ketan Chandak yes it is....do provide the solution...
- Soumyabrata Mondal but for this ans Vs=37.64
- Soumyabrata Mondal how Vs can be 37.64????