elasticy

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a mass is suspended from a wire .change in length of wire is Î”l.now the same wire is stetched to double its length and the same mass is suspended from the wire.the change in length in this case will become

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Lokesh Verma ·2009-08-25 07:48:02

use (F/A)/(Î”L/L) = Y as constant.

then see the inital case A and the 2nd case A.

F/(A/2)Î”L'/2L=F/AÎ”L/L

4Î”L'=1Î”L

Î”L'=4Î”L

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matrix .............. ·2009-08-25 23:27:46

correct sir

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