first case A(P+ÏgH)
2nd case d(mv/dt) = dm/dt . v = ÏA √2gh . √2gh = 2 ÏA gh
So the ratio will be P/ÏgH + 1
The opening near the bottom of the vessel shown in figure has an area A.A disk is held against the opening to keep the liquid from running out.Let F1 be the net force applied on the disc applied by liqiud an air in this case.Now the disc is moved away from the opening to a short distance.The liquid comes out and strikes disc inelastically.Let F2 be the force applied by liquid on disc in this case.Find F1/F2.
first case A(P+ÏgH)
2nd case d(mv/dt) = dm/dt . v = ÏA √2gh . √2gh = 2 ÏA gh
So the ratio will be P/ÏgH + 1
yeah they have ignored P and he has mistyped the result.. slightly
It will be 2... look carefully :)