1I think I have seen this problem some where.
find the time taken by cylinder to reach O from A . ( g=10ms-2)
OA =5m.
unable to proceed.
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6 Answers
We have to first resolve the gravitational force mg into 2 components one in that slant plane & another normal to that plane.
The component in that plane will be mg Sin30°
The other normal component will be mg Cos30° but we are least interested in that.
Now again we have to resolve mg Sin30° into 2 component, the component in the direction OA will be mg Sin30° * Cos60°
Only this componet of force will cause motion in the cylinder.
So, Accelearation = g Sin30° * Cos60° = g * 1/2 * 1/2 = 2.5 m/s2
Just 1 line of calculation after this..... [1]
Cheers
1I am not able to visualize how you have taken the two components.
Please explain a bit more
Try to think logically, you will get it.
I didn't put the picture of resolved forces coz that would be spoon feeding [1]
Think .... think ...
