Fluids--2

JEE Main 2015 Guidance › Mechanics questions › Fluids--2

a cubical block of wood of edge 3cm floats in water.The lower surface of cube just touches the free end of a vertical spring fixed at the bottom of pot.Find max weight that can be put on the block without wetting it.Density of wood=800 kg/m3 and spring constant=50N/m

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Asish Mahapatra ·2009-08-05 01:17:17

Draw the FBD in that condition:
kx upwards, mg of block + m'g of weight downwards and B buoyant force upwards.
kx = 50*(3*10^-2) = 1.5 N upwards
mg of block = VÏg = (3*10^-2)³*800*10 = 0.216N downward
m'g = m' is to be calculated
B = VÏ_wg = (3*10^-2)³*1000*10 = 0.27N upward

Considering equilibrium,
1.5-0.216-10m'+0.27=0
or m' = 0.1554 kg

Calculation mistakes possible

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champ ·2009-08-05 01:20:33

no
ans is m'=0.035 kg

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Fluids--2

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