Fluids-2 (Jee Mains-2014)

I did this by playing with the options. Putting α=0, options 2 and 4 can be eliminated. Now, if α=45°, then it means that d₂=0, as COM of liquid d₁ would then be at the lowest point. That leaves us with option 3 as the answer.

take the point of intersection of the liquids...let it be A..take another point at the same horizontal level(on other side of tube)..let it be B..
now P_A=P_B..(same horizontal level)
P₀+d₁gh₁=P₀+d₂gh₂
now h₁=Rcosα-Rsinα
&h₂=Rcosα+Rsinα(h₁,h₂ is found using the fact that both of them subtend a right angle at the centre..)
this gives...(c) as the answer..

Sir, is the tube accelerating towards the left?
Otherwise how can we get such a slanting surface?