A1v1=A2v2
if area decreases v increases.. and by Bernaul'is theorem.. if v increase P decreases
STATEMENT:for an ideal fluid flowing thru a horizontal pipe of non uniform cross section,the pressure decreases with decrease in cross section
i found this statement in an assertion reason qn and it is given that it is true,can anyone explain how?
A1v1=A2v2
if area decreases v increases.. and by Bernaul'is theorem.. if v increase P decreases
But whatever be the flow.. if fluid is ideal... mass conservation can be applied... and although bernaulli's theorem can't be applied in non streamlined flow.. but then also pressure decreases( i think)
full qn
STATEMENT 1:for an ideal fluid flowing thru a horizontal pipe of non uniform cross section,the pressure decreases with decrease in cross section
STATEMENT 2:Speed decreases with increase in cross section
it is true.....
See. P1 + (1/2)Ï(v1)2 = P2 + (1/2)Ï(v2)2 ...... (i)
As, fluid is ideal.... hence
A1v1 = A2v2 ...... (ii)
As, in statement 1, pressure decreases, hence speed will increase.......(from eqn (i))
Hence area of cross section should decrease (.....from equation (ii))
Hope u cud understand.