fluids - conceptual

A₁v₁=A₂v₂

if area decreases v increases.. and by Bernaul'is theorem.. if v increase P decreases

cant be said becos the nature of flow is not mentioned

thanks, priyam

sankara,the fluid is non viscous

But whatever be the flow.. if fluid is ideal... mass conservation can be applied... and although bernaulli's theorem can't be applied in non streamlined flow.. but then also pressure decreases( i think)

full qn

STATEMENT 1:for an ideal fluid flowing thru a horizontal pipe of non uniform cross section,the pressure decreases with decrease in cross section

STATEMENT 2:Speed decreases with increase in cross section

it is true.....
See. P₁ + (1/2)ρ(v₁)² = P₂ + (1/2)ρ(v₂)² ...... (i)
As, fluid is ideal.... hence
A₁v₁ = A₂v₂ ...... (ii)

As, in statement 1, pressure decreases, hence speed will increase.......(from eqn (i))
Hence area of cross section should decrease (.....from equation (ii))

Hope u cud understand.