1NOTE:VELOCITY OF WATER AT BOTH TANKS CAN BE NEGLECTED SINCE WATER COMES OUT OF A TINY HOLE SO V1 AND V2=0(VERY CLOSE)
LET VELOCITY OF EFFLUX BE V
SO APPLYING BERNOULLIS THEOREM:
P1+pg(h+h1)=P2+pg(h+h2)=P+pV2/2
solving it we get ans. as i posted in #3
1
JOHNCENA IS BACK
·2009-05-01 10:28:42
@gordo
thinking that only i wrote equations accordingly..............
see #15 ......[1]
1@sriraghav do u notice the pressure at the bottom most point of the two cylinders, Pa=P1+dgH1
Pb=P2+dgH2
do u see that the 2 pressures are different...now observe the direction of motion of the liquid in the 1st cylinder, left to right...
motion of liquid in the 2nd cylinder is from right to left,
so after all this, Do u really think this is stream line motion i mean there are 2 different directions for motion,and its not a pressure equilibrium situation, so untill we have a situation where P1 + H1dg= P2+H2dg we cannot apply the bernoulis theoram at the hole point...
cheers!!!
1
JOHNCENA IS BACK
·2009-05-01 10:15:41
but ya exact velocity when calculated if area of cross section be given wud not be too different from one i posted in #3 coz then u will get ratio of area of cross section which again you will have to assume as zero................................................n finally ans. will be same as wat i gave in #3...
1
JOHNCENA IS BACK
·2009-05-01 10:13:16
hey richa i wud have given exact velocity had the area of cross section be given.got it!!!!!!!!!...it is not at all difficult.
1ya ankit is correct the net velocity will nt be exactly wat john has calculated as water has to cum out thru a single hole so the flow is not independent .n thus net velocity must be sumwat less than tht calc(bt i dunno how to find it exactly)
1
JOHNCENA IS BACK
·2009-05-01 10:01:55
ur case will work for 2 holes john ... can u take the single hole as two holes !!
i mean wat do u mean by bold words
1. dont waste ur time on this mybrain-made Q.....i just had the doubt!!
1pata nahi ! i am totally confused .. not intrested as no one knows wat is correct !
1
ANKIT MAHATO
·2009-05-01 09:51:37
ur case will work for 2 holes john ... can u take the single hole as two holes !!
1
JOHNCENA IS BACK
·2009-05-01 09:51:08
@sriraghav
is it ok.....................
1
JOHNCENA IS BACK
·2009-05-01 09:50:38
i have taken h in #15 so am posting relevant image also
1p1 + h1Ïg + p2 + h2Ïg = P + 1/2 Ïv2
1
sriraghav
·2009-05-01 09:43:16
i donno the ans john... i wanted someone to post the soln...NOTE IT is my own Q>>>>:D
1
JOHNCENA IS BACK
·2009-05-01 09:42:26
BHAI CORRECT ANSWER(ACCORDING TO U[1]) PLZ TELL
1
JOHNCENA IS BACK
·2009-05-01 09:40:55
I DON THINK ANYTHING IS MISSING.BUT U GAVE EXTRA INFORMATION(h3[3])
1
sriraghav
·2009-05-01 09:38:26
my own Q, i needed the steps pls....
I wanted to know whether it is just the straight Bernoulli derivation or some other thing will b there....
Sorry for makin ur brains confused!!
I want the soln...
If anything relevent is missin pls add up... i dont mind:P
1
JOHNCENA IS BACK
·2009-05-01 09:37:51
let's wait for sriraghav's reply.
i wonder he is online since such a long time n not replying.
1
ANKIT MAHATO
·2009-05-01 09:35:41
john i think ur's is correct !
1
ANKIT MAHATO
·2009-05-01 09:34:24
sky ur answer is incorrect ! something fishy is there in this question ..
1
JOHNCENA IS BACK
·2009-05-01 09:25:35
gordo bhaiya........wat is ur answer!!!!!!!
1
gordo
·2009-05-01 09:20:33
@sriraghav, is this an origional Q. or u made it up?
1
JOHNCENA IS BACK
·2009-05-01 09:09:49
velocity of efflux={2[P1-P+(rho)gh1]/(rho)}1/2={2[P2-P+(rho)gh2]/(rho)}1/2
