pressure exerted by water will rise the mercury
the raised mercury will be equally distributed to the two arms
27.2*1*A=13.6*2h*A
h=1cm
can someone please explain to me hot to do this question
An open u tube has some mercury in it. 27.2 cm water is filled in one of it ends. How high does the mercury rise in the other tube?? density of mercury is 13.6 g/cc and density of water is 1 g/cc.
Ans. 1 cm
please xplain to me what is the main logic in solving these type of probs..
pressure exerted by water will rise the mercury
the raised mercury will be equally distributed to the two arms
27.2*1*A=13.6*2h*A
h=1cm
why will it be distributed to the two arms ??? what exactly is wrong if i apply the following?
Ïwater hwater g = Ïmercury hmercury g
i still don't understand,
here's what i understand of the q. We have an open tube containing mercury and we put water in one arm. All that happens is that the mercury in the other end moves up and equals the height of the water. what is wrong in this interpretation???
[7][7][7]
sorry...i told rubbish in previous post
actually the pressure in each column has to be the same...so the excess pressure exerted by water...is to be distributed equally