24ya anirudh...i too marked √2gh but ans is none of these....and i dont know whats that..
for 2 u r wrong too[2]
Q1 A open tank having non viscous liquid to height 5m is palced over gorund.A heavy spherical ball falls from height 40m over the ground in tank.Find height to which ball will go back.Collison b/w ball and bottom of tank is elastic
Q2 There is a horz film of soap soln.On ita thread in form of loop is placed.The film is pierced inside loop and thread becomes circular loop (R).Surface tension=T,find tension in thread
Q3 Find velocity through small hole S
-
UP 0 DOWN 0 0 11
11 Answers
13) shouldn't it be plain
v=√2gh
2)
if we consider a semicirclrcular part of the loop
net tension inwards = 2F
and net force surface tension by taking its projection on the diameter =
2T*(2R= 4TR
2F=4TR
=>F = 2TR
24
1A2. is F=TR?
Let the tension in the string be F.
net force on the element of length R d(theta) is F d(theta) towards the centre along the x axis.
In this case this force is balanced by surface tension pulling the string in the other direction, T R D(theta)..
F d(theta) = T R d (theta)... or F = T R
1hey bhaiya can't find my mistake in 2)
for 3)
the pressure in the test tube above liquid shoule be zero .
when applying bernoulli at the hole and top of liquid
Ïgh+0+0=P0+ 1/2Ïv2
v=√2gh-(2P0/Ï)
now i hope it is correct?
106yup now anirudh's ans is correct for Q3...
Initially, the pressure above the liq column is zero
24ya anirudh ...u r rite now...i missed that point where pressure =0
ya rahul u r rite
1Q1. I think it will rise to the same height, 40m.as the liq. is non-viscious, so no viscious force.
Collision with the bottom elastic.
As the balls r heavy,buoyancy will be very small.So energy of the ball is conserved.
49isn't dat quite obvious due to presence of two layers in soap film not 1 layer...[1]