fluids revision

Q1. A large open top container of negligible mass and uniform cross-sectional area A has a small hole of cross-sectional area A/100 in its side wall near the bottom. The container is kept on a smooth horizontal floor and contains a liquid of density ρ and mass m0. Assuming that the liquid starts flowing out horizontally through the hole at t=0, calculate:
(i) the acceleration of the container
(ii) the velocity when 75% of the liquid has drained out.

45 Answers

1
Terminator ·

Sanky.......???....[9][9][9][9][9].......lolzzzz..........

106
Asish Mahapatra ·

eureka cud u explain more??

24
eureka123 ·

v=√2gh
F=ρv2A/100
acc.=F/mo

put mo/Ah =ρ

=>acc. =g/50

24
eureka123 ·

sory ashish vo pehla post galat tha...........mujhe laga approx. nahin karna tha....isliye ulta ans..............but this is 1000% correct

1
Debasish Shanti ·

Velocity of fluid through the hole will be root of (2gh).
Now apply conservation of linear momentum.

106
Asish Mahapatra ·

thx for (i) of Q1.

24
eureka123 ·

Q1 part 2 ans kya hai???

106
Asish Mahapatra ·

gm0/2Aρ

33
Abhishek Priyam ·

in question 2 mass m is attached in lower end of rod... ?

24
eureka123 ·

asish hame velocity container ka batana hai naa????

33
Abhishek Priyam ·

are uska double aa raha hai..

2√gm0/2Aρ

[2]

106
Asish Mahapatra ·

in Q2. nothing else mentioned .... yes u have to find vel. of container i think,....... plz also find vel. of liquid coming out ..... if possible

33
Abhishek Priyam ·

no fig also...

okie... it should be at bottom only... fro equillibrium..

1
Terminator ·

[1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1][1]

1
Terminator ·

i'll terminate this thread....

.......hahahq

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