force n friction

two particles A and B of the same mass are joined by a light string and placed on a horizontal surface. An external horizontal force P acts on A. the tension in the string is T.
the force of friction acting on A and B are F1 and F2 respectively.
The limiting value of F1 and F2 is Fo.
As P is gradually increased,
a) for P<Fo, T=0
b) for Fo <P <2Fo , T=P-Fo
c) for P>2Fo, T=P/2.
d) n.o.t..
(ans is a,b,c. … I got a and c… no clue about b !~#@$!!!!!)

5 Answers

106
Asish Mahapatra ·

sky
pls clarify option (a) what is it?

1
Akand ·

i dint understand option a.........may be u dint type properly.....

1
skygirl ·

As P is gradually increased,
a) for P < Fo , T = 0
b) for Fo < P < 2Fo , T= P - Fo
c) for P > 2Fo, T = P/2.
d) n .o. t..
( ans is a ,b ,c. … I got a and c… no clue about b !~#@$!!!!!)

106
Asish Mahapatra ·

(a)
take FBD of mass in right...
The forces are.. P to right... and friction towards left and tension towards left... And as P<F0 so, friction = P hence T=0

(b)
If F0<P<2F0 then again FBD of right mass..
the forces are P to right... F0 to left and T to left... and as P<2F0 so system is in equilibrium...
Hence P=T+F0 == > T=P-F0

(c)
P>2F0 ==> net acceleration is (P-2F0)/2m
Take FBD of right mass...
P to right, T and F0 to left
So, P-T-F0 = m.(P-2F0)/2m
==> P-T-F0 = P/2 - F0
==> T = P/2

so ans is (a),(b),(c)

1
skygirl ·

tx :)

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