4√5N
- Akash Anand Good Work
8 N normal to the surface and
4 N frictional force along the surface towards the upward direction
4 N
Contact force is basically the resultant of Normal force and frictional force...
N=mgcos37°=8N
f=4N
Fc=√(N)^2 + f^2 [where Fc is d contact force]
Fc=4√5N
Vertical to the incline,
R= 4/5*10= 8 N
Along the incline
f= 0.5*R= 0.5*8= 4 N
Net Contact Force= √[ f2+R2 ]
=>√(16+64)= √80 =4√5 N