Friction

BITSAT Answers › Mechanics questions › Friction

A 60kg body is pushed with enough force to start it moving across a floor and it continues to act afterwards. The coefficient of static friction is 0.5 and the coefficient of sliding friction is 0.4 . Calculate the acceleration of the body.

#Physics #Mechanics #Kinematics

UP 0 DOWN 0 0 2
Post on FacebookPost anonymously?

2 Answers

466

Himanshu Giria ·2014-06-20 09:56:34

1 m/s²

UP 1 DOWN 1
ARKADYUTI BANDYOPADHYAY Thanks,my answer was correct. Can you please show me how you worked out THIS question?
Upvote·0· Reply ·2014-06-20 20:16:38
Post on FacebookPost anonymously?

146

Amartya Kumar Mistry ·2014-06-20 22:16:11

we know for static frictional force f=Î¼smg from here we get f=300(N)
for sliding friction f=Î¼kmg which is=240
now net force on the block=(300-240)=60(N) then from nlm acc=60/60=1m/s2

UP 0 DOWN 1
ARKADYUTI BANDYOPADHYAY Thanks for showing. I did exactly in the same way. By the way,stupid question,but,value of k is 1 in the SI system,right? (meaning if other units are taken in the SI system?)
Upvote·0· Reply ·2014-06-20 22:20:54
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

Friction

2 Answers

Your Answer

Add Image

Similar Questions