71equipotential plane ? Does it mean it returns to same level or height? :P
By the way, You in Edudigm?
well first of all a short introduction to this man....
Ravish Bhaiya is the new physics teacher in Edudigm....in my life i have never seen a person with such a great command over the subject as him...
one question he gave to me in last day class....
a body is projected at an angle (90-θ) with the uniform gravitational field existing in a region of space...the projection velocity is v...
the particle is stopped on the same equipotential plane from which it started moving....
find the length of path traversed by the body during the flight!!!
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7 Answers
71
49yea me in edudigm...
equipotential plane here means the plane joining all the points having same gravitational potential!!
71Of course, If they at same height then only they are in equipotential plane?
49here there is no frame of reference like earth to define height...
but yeah your bhawna is correct!! ;)
@vivek: so everyone is nowadays copying rajiv bhaiya's status??? :P
71Hhaahaha!
here there is no frame of reference like earth to define height...
Let define the launch Plane as the reference frame?
1it snothing but a sum with dirty integration assuming the nagle to be theta instead of 90-theta as it makes no apparent difference
\left|v \right|=\left|ucos\theta i +(usin\theta -gt)j \right|
thereofre distance travelled is
\left|v \right|dt=\left|ucos\theta i +(usin\theta -gt)j \right|dt
more appropriately we hv to calculate the distanc esperately when v(y) is +ve and when it is -ve
so the answer comes up to ...u^{2}sin\theta (2cos\theta +sin\theta )/g
now taking into account that we hv assumed that we assumed the angle t be angle 90-@
so we now take that into account
so answer comes up to
u^{2}cos\theta (2sin\theta +cos\theta )/g
isnt it.......?