A pendulum bob (mass m)at its mean positon is given velocity v=√7gl/2 .Calculate the height at which it leaves circular path..
Just give the answer first,,,I want to confirm mine...
1Well, Sankara.. the path should follow the direction of velocity which will be normal to the thread. And it leaves the circular path and enters a parabolic path.
In fact, there can be another interesting problem where you have to find the initial velocity given at the mean position of the ball such that it leaves the circular path and passes through the point of poivot during the parabolic path.
62no sankara..
There will be 2 forces on the mass..
mg and T
T will be zero when it will just leave the circular path.....
mg will be downward... of which the component has to be taken...
i am sorry but mg/sinθ is a totally wrong concept.. it is not a concept at all.. it is a sin to think of force as that!
62
I know that the contrast is very low.. but still try to see if it works :)
3yes eureka i am wrong with my ans without understanding the question clearly.
i will post the diagram that would help u
from where is the height to be measured
3can u post ur soln so that we can discuss wat mistake done by us.
my soln.
24my answer is diff from u................................
but one thing common in all......we all are getting wrong answer.......correct answer is 27/16l
