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i hope tat these graphs given are pure parabolic.....

for first graph eq of the curve is x²=kv

for second graph eq of curve is x=kv²

for third graph eq of curve is t=kx

for fourth graph eq of curve is t²=kv

for first graph........

differentiate x²=kv wrt to x

2x=kdv/dx
2xv=ka.........................since a=vdv/dx
2x³/k²=a

hence acceleration is non uniform and is proportional to x

for second graph

again differenting wrt x

1=2kvdv/dx
1/2k=a

hence accelration is constant

for third graph

differentiate wrt t

1=kdx/dt

again differentiating wrt t will give acceleration as 0

henceaccelration of particle is 0

for fourth graph

t²=kv

differentiate wrt t

2t=kdv/dt

2t/k=a

hence accelration proportional to t and non uniform