Time period of a pendulum = (something)√l/g
g = GM/R2
R' = 2R and M' = 2M
Hence, g' = g/2 => T' = √2T = √2 seconds.......
Anything wrong in this solution?
The mass and radius of a planet are twice that of the earth Then the period of oscillation of a seconds pendulum on that planet will be ans given is √2 sec But i think the ans should be 2 sec only Because it is the only time period of seconds pendulum
Time period of a pendulum = (something)√l/g
g = GM/R2
R' = 2R and M' = 2M
Hence, g' = g/2 => T' = √2T = √2 seconds.......
Anything wrong in this solution?
you haven't put the value of T according to your equation ans should be 2√2 sec