hcverma

nishant bhaiya plz post the correct solution of HCVERMA(kinematics)

exercise question no.-44

10 Answers

11
virang1 Jhaveri ·

See if the ball hits the the nth then y = n-1 since the ball is already a 1m high
x = 110 + y

x = 35* 3/5 * t
x = 21t

y = 35*4/5*t - 4.9t2
y = 28t - 4.9t2
21t = 28t - 4.9t2 +110
4.9t2 - 7 t - 110 = 0
t =5.5
y = 154 - 148.225
y = 5.775
n -1 = 5.8
n = 6.8
therefore the sixth bench

1
JOHNCENA IS BACK ·

yup that's prob i m facing .6.8 i.e.it will 7th step(think carefully).but ans. is 7th

11
virang1 Jhaveri ·

the answer is sixth

11
virang1 Jhaveri ·

See it has to be rounded to the lower integer since the height is inadequate for the 7th step but perfectly adequate for the 6th

1
JOHNCENA IS BACK ·

tell me y??????n=6.8
then ans. is 7 clearly.

1
JOHNCENA IS BACK ·

waah bhai ans. laane ke liye kuch bi karenge kya.

11
virang1 Jhaveri ·

See if y = 6.8
At that time
x = 21*5.5
x = 115.5
Rite?

Noe first bench is at 110m
Therefore 5.5m into the stadium
Each bench is 1m wide
Therefore 5.5th bench therefore it is the 6th bench

11
virang1 Jhaveri ·

one more think
Step 1 is between 110 and 111
Step 2 is between 111 and 112
Step 3 is between 112 and 113
Step 4 is between 113 and 114
Step 5 is between 114 and 115
Step 6 is between 115 and 116

1
JOHNCENA IS BACK ·

here is the right one

See if the ball hits the the nth then y = n-1 since the ball is already a 1m high
x = 110 + n=110+y+1 i.e. y=x-111

x = 35* 3/5 * t
x = 21t

y = 35*4/5*t - 4.9t2
y = 28t - 4.9t2
21t = 28t - 4.9t2 +111
4.9t2 - 7 t - 111 = 0
t =5.5

x=21*5.5=115.5

n=115.5-110=5.5

therefore the sixth bench

1
JOHNCENA IS BACK ·

nishant sir check

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