one possible explanation:
rod cannot elongate, so velocity along rod must be constant.
So if we take vel of A in horizontal direction (v1)
and v2=3 m/s
v1= v2 cos 60
= 1.5 m/s
Let there be a rod of length l(in a horizontal plane).End B is given a velocity 3m/s at an angle of 60 degrees in horizontal plane(+ve direction).
What is he minimum velocity of end A?
Ans.1.5 m/s
Please provide an explanation.
one possible explanation:
rod cannot elongate, so velocity along rod must be constant.
So if we take vel of A in horizontal direction (v1)
and v2=3 m/s
v1= v2 cos 60
= 1.5 m/s
Thanks for the soln..
But could you simplify your explanation a bit more?